find the equation of the line passing through the point (-4,3)with slope 1/2
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Answered by
34
eq of line passing through a point x1,y1 and of given slope m is
(y-y1)=m(x-x1)
y-(-4)=1/2(x-3)
y+4=1/2(x-3)
2y+8=x-3
x-2y-11=0
dszala:
thank you for helping me
Answered by
26
By point slope form i.e., (y-y1)=m(x-x1)
(y-3)=1/2(x-(-4))
2y-6=x+4
x-2y+10=0
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