Question

Find the equation of the line passing through the point (-4,-5) and perpendicular to the line joining
the points (1, 2) and (5, 6).

Answer 1

Answer:

x+y+9=0

Slope=6-2/5-1

=4/4 =1

1*m2=-1(since the lines are perpendicular)

=m2=-1

Equation

(y-y1) =m2(x-x1)

(y+5)=-1(x+4)

y+5=-x-4

x+y+9=0