Question

Find the equation of the line passing through the point (6 3) perpendicular to the line 4x-5y=-10

Answer 1

HAY BUDDY..

Step-by-step explanation:

Given Line:4x-5y=-10

4x=5y-10

x=5/4y-10/4

therefore, Slope(m1) =5/4

Let slope of the line perpendicular to give line be m2.

We Know that,

m1×m2=-1 (in case of perpendicular lines)

5/4×m2=-1

m2=-4/5

Equation of line passing through (6,3) and perpendicular to the line 4x-5y=-10,

y-y1=m(x-x1)

y-3=-4/5(x-6)

5(y-3)=-4(x-6)

5y-15=-4x+24

4x+5y-15-24=0

4x+5y-39=0 (Required equation of line )

HOPE IT HELPS..

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