find the equation of the line passing through the points (-2, 6 ) and (4, 8)
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Answer:
5x+y+13=0
Step-by-step explanation:
Let A=(−2,−3)=(x
1
,y
1
)
B=(−4,7)=(x
2
,y
2
)
Equation of a line in two point form is
y−y
1
=
x
2
−x
1
y
2
−y
1
(x−x
1
)
⇒y+3=
−4+2
7+3
(x+2)
⇒y+3=−5(x+2)
⇒y+3=−5x−10
∴5x+y+13=0 is the required equation.
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