find the equation of the line passing through the points (3,-7) and (-2,-5)
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the equation of a line in
slope-intercept form
is.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
y
=
m
x
+
b
2
2
∣
∣
∣
−−−−−−−−−−−−−−−
where m is the slope and b the y-intercept
to calculate m use the
gradient formula
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
m
=
y
2
−
y
1
x
2
−
x
1
2
2
∣
∣
∣
−−−−−−−−−−−−−−−−−
let
(
x
1
,
y
1
)
=
(
3
,
−
7
)
and
(
x
2
,
y
2
)
=
(
−
2
,
4
)
⇒
m
=
4
−
(
−
7
)
−
2
−
3
=
11
−
5
=
−
11
5
⇒
y
=
−
11
5
x
+
b
←
partial equation
to find b substitute either of the 2 given points into
the partial equation
using
(
−
2
,
4
)
4
=
22
5
+
b
⇒
b
=
−
2
5
⇒
y
=
−
11
5
x
−
2
5
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