Question

Find the equation of the line passing through the points
(a cosa, a sin a) and (a cos B, a sin B).


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Answer 1

We know that :-

$\tt \: Equation \: of \: line \: passing \: through \: points \: (x_1 , y_1) \: and \: (x_2 , y_2) : \\ \\ \boxed { \boxed {\tt \large\longrightarrow y - y_1 = (x-x_1)\bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg )}} \\ \\ \tt \rightarrow \: here \: \bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg ) is \: slope \: of \: line$

Now, here :-

$\bull \: \: \tt x_1 = a \: Cos A \\ \\ \bull \: \: \tt y_1 = a \: Sin A\\ \\\bull \: \: \tt x_2 = a \: Cos B \\ \\\bull \: \: \tt y_2 = a \: Sin B$

$\tt \longrightarrow y - a \: Sin \: A = (x-a \: Cos A)\bigg( \dfrac{a \: sin B-a \: sin A}{ a \: cos B -a \: Cos A} \bigg )$

$\tt \longrightarrow y - a \: Sin \: A = (x-a \: Cos A)\bigg( \dfrac{ \: sin B- \: sin A}{ \: cos B - \: Cos A} \bigg )$

$\tt \longrightarrow( y - a \: Sin \: A )(cos B - \: Cos A)= (x-a \: Cos A)( sin B- \: sin A)$

Answer 2

Answer:

y is ur mood off

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