Question

Find the equation of the line perpendicular to 5x− 3y + 1 = 0
and passing through the point (4,−3).
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Answer 1

hey friend!
YOUR answer》


5 x -3y+1=0
-3y=-5x-1
3y=5x+1
y=(5x+1)/3
or
y=5x/3+1/3
slope of y=-3
given points is (4,-3)
so (y+3) = -3 (x-4)
y+3=-3x+12
y+3x=9
3x+y=9
is the required equation.

HOPE it helps you.