Find the equation of the line perpendicular to the line 2x + y - 1 is equal to zero and passing through the point of the intersection of the line x + 2 y - 1 is equal to zero and y is equal to x
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EQUATION OF A LINE PASSING THROUGH THE INTERSECTION OF TWO LUNES IS GIVEN BY
A1 + K A2 = 0
WHERE A1 = x + 2y -1 = 0
AND
A² = y - x = 0
___________________________________
x ( 1 - k ) + y ( 2 + k ) - 1 = 0
NOW IT IS GIVEN THAT THIS LINE IS PERPENDICULAR TO 2x + y - 1 = 0
=>
( k - 1 ) / ( 2 + k ) = -2
=>
k - 1 = -4 - 2k
=>
3k = -3
=>
k = -1
=>
x ( 1 + 1 ) + y ( 2 -1 ) -1 = 0
=>
2x + y -1 = 0
SO, EQUATION OF A LINE PASSING THROUGH THE INTERSECTION OF TWO GIVEN LINES AND PERPENDICULAR TO THE GIVEN LINE IS
2x + y -1 = 0
______________________________
EQUATION OF A LINE PASSING THROUGH THE INTERSECTION OF TWO LUNES IS GIVEN BY
A1 + K A2 = 0
WHERE A1 = x + 2y -1 = 0
AND
A² = y - x = 0
___________________________________
x ( 1 - k ) + y ( 2 + k ) - 1 = 0
NOW IT IS GIVEN THAT THIS LINE IS PERPENDICULAR TO 2x + y - 1 = 0
=>
( k - 1 ) / ( 2 + k ) = -2
=>
k - 1 = -4 - 2k
=>
3k = -3
=>
k = -1
=>
x ( 1 + 1 ) + y ( 2 -1 ) -1 = 0
=>
2x + y -1 = 0
SO, EQUATION OF A LINE PASSING THROUGH THE INTERSECTION OF TWO GIVEN LINES AND PERPENDICULAR TO THE GIVEN LINE IS
2x + y -1 = 0
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