Question

Find the equation of the line perpendicular to the line 3x + 4y+6=0 and making an intercept
-4 on the X - axis.

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Answer 1

Step-by-step explanation:

Slope of 3x+4y+6=0,

m1=4−3

Let slope of required line be m2

As the two lines are perpendicular ⇒m1m2=−1

⇒m2=34

and the line passes through (−4,0)

⇒ Its equation: y=0=34(x+4)

⇒3y=4x+16.

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