find the equation of the line perpendicular to the line x-2y+3=0and passing through the point (1,-2)
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Let the required line be y=mx+c
y=mx+c and x−2y−3=0 are perpendicular
⇒ m
1
×m
2
=−1
m
1
=mm
2
⇒ y=
2
1
(x−3)
m
2
=1/2
∴ m(1/2)=−1
∴ m=−2
line passe through (1,−2)
y=−2x+c ⇒ −2=−2(1)+c
⇒ c=0
∴ y=−2x
∴ The required line equation is y=−2x
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