Question

find the equation of the line perpendicular to the line x-2y+3=0and passing through the point (1,-2)​

Answer 1

Answer:

Let the required line be y=mx+c

y=mx+c and x−2y−3=0 are perpendicular

⇒ m

1

×m

2

=−1

m

1

=mm

2

⇒ y=

2

1

(x−3)

m

2

=1/2

∴ m(1/2)=−1

∴ m=−2

line passe through (1,−2)

y=−2x+c ⇒ −2=−2(1)+c

⇒ c=0

∴ y=−2x

∴ The required line equation is y=−2x