Question

Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5).

Answer 1

the answer is in the image.

Answer 2

Answer:

Y=-5x-5

Step-by-step explanation:

We know the equation of a line is y=mx+b

So we change the x-5y=15, into the proper equation of a line format like this:

x-5y=15 (add 5y)

x=15+5y or 15+5y=x (subtract 15)

5y=x-15 (divide by 5)

y=1/5x-3

Now that we have the equation of the original line, we find the perpendicular. To find perpendicular, you use the negative reciprocal instead for the first part. We now know the first part of the equation will be y=-5x. We just need to find what the y intercept is.

If we draw a coordinate plane, and mark these points out, we can tell that the slope is negative, which means it will be in the third quadrant. Then you mak the line.

The line should pass through -5 on the Y axis is you plotted the other point (-2,5) correctly.

Hope this helps!