Question

Find the equation of the line perpendicular to x-7y+5=0 having the x-intercept 3...

Answer 1

To find the Equations of the line perpendicular to the line x-7y+5=0

Therefore slope of the line x-7y+5=0
7y= - x - 5
y = (-x)/7 - 5/7
Slope(m1) = -1/7. (coefficients of x)
m1 × m2= -1. (Perpendicular
condition)
m2 = 7;. x-intercept is 3
The point is (3,0)

Equations formula
y- y1 = m(x - x1)
y- 0 = 7(x - 3)
y = 7x - 21 is the Equations of the line

Answer 2

The required equation is $7x+y-21=0$

Step-by-step explanation:

The equation of the line perpendicular to $x-7y+5=0$ having the x-intercept 3.

Re-write given equation as,

$y=\frac{1}{7}x+\frac{5}{7}$

Comparing equation with general form, $y=mx+c$

So, The slope of line is $m=\frac{1}{7}$.

We know if two lines are perpendicular then $m\times m_1=-1$

Substitute the value,

$\frac{1}{7}\times m_1=-1$

$m_1=-7$

So, equation of the required line,

$y=-7x+c$

We are given x-intercept is 3.

So, when x=3,y=0

Substitute in equation,

$0=-7(3)+c$

$c=21$

Equation of the required line is $y=-7x+21$

or $7x+y-21=0$

Therefore, the required equitation is $7x+y-21=0$

#Learn more

Straight lines

https://brainly.in/question/2638565, Answered by Wifilethbridge