Question

Find the equation of the line perpendicular to x - 7y + 5 = 0
and having r-intercept 3.
​

Answer 1

Answer:

y = - x + 3

Step-by-step explanation:

x - y + 5 = 0

y = x + 5 [rearranged in the form y = mx + c ]

perendicular lines = m1 . m2 = -1

m1 = 1        m2 = ?

m2 = -1/m1

m2 = -1 /1

m2 = -1

y = -1 x + 3

Answer 2

Answer:

7 x + y - 21 = 0

Step-by-step explanation:

The equation of line perpendicular to x - 7 y + 5 = 0 is 7 x + y + λ = 0

Given :

x-intercept is 3. It means that line is passing through point on x- axis ( 3 , 0 )

Putting value of x = 3 and y = 0 in 7 x + y + λ = 0

= > 21 + 0 + λ = 0

= > λ = - 21

On putting value of λ = - 21 we get :

7 x + y - 21 = 0

Therefore , we get required equation .