Question

Find the equation of the line that is parallel to y=7−5x and passes through the point (6,-21). Give your answer in the form y=mx+c

Answer 1

We know the slope is -5 and it passes (6,-21).

When we know the slope and its passing point, we use the point-slope form.

Point-slope form: $y+21=-5(x-6)$

$\implies y+21=-5x+30$

$\implies y=-5x+9$

More information:

• Point-slope Form

When we know its passing point and slope.

$\implies y-\underline{y_1}=\underline{m}(x-\underline{x_1})$

$(x_1,y_1)$ is a point.

$m$ is a slope.

• Point-intercept Form

When we know its y-intercept and slope.

$\implies y=mx+\underline{b}$

$b$ is a y-intercept.

Answer 2

$\large \red{ \mathfrak{ \underline{ \underline{Hi \: \: dear \: \: user!!!}}}} \\ \\ \large \mathtt {\underline{Answer}}$

We know the slope is -5 and it passes (6,-21).

When we know the slope and its passing point, we use the point-slope form.

Point-slope form: $y+21=-5(x-6)$

$⇒y+21=-5x+30$

$⇒ y=-5x+9$

More information:

Point-slope Form

When we know its passing point and slope.

$⇒ y-\underline{y_1}=\underline{m}(x-\underline{x_1})$

$(x_1,y_1)$ is a point.

$m$ is a slope.

Point-intercept Form

When we know its y-intercept and slope.

$⇒ y=mx+\underline{b}$

$b$ is a y-intercept.

HOPE SO IT WILL HELP