Question

Find the equation of the line that is perpendicular to 2x−3y+6=0 and goes through the pointP(3,5)

Answer 1

Answer:

2y + 3x =19

Step-by-step explanation:

as the line is perpendicular, so the slope of the required line will be the negative reciprocal of the given line's slope.

so

slope will be m = -3/2

equation will be

y - 5 = (-3/2)(x - 3)

=2y + 3x = 19

= 3x + 2y = 19