Question

Find the equation of the line that passes through (2, -1) whose slope is 2/3?

Answer 1

Answer:

2x - 3y - 7 = 0

Step-by-step explanation:

We are given that a line passes through the point (2, -1) and has slope of 2/3. We have to write the equation of the line.

By slope point form, we have:

$y - y_1 = m(x - x_1)$

Here,

• x and y are variables
• x1 = 2
• y1 = -1
• m = 2/3

By substituting the known values, we get:

$\implies y - (-1) = \dfrac{2}{3}(x - 2)$

$\implies 3(y + 1) = 2(x - 2)$

$\implies 3y + 3= 2x -4$

$\implies 0= 2x - 3y -4 - 3$

$\implies 0= 2x - 3y -7$

This is the required equation of straight line.

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