Question

Find the equation of the line through (2,−3) and (−1,4).

Answer 1

Answer:

7x-3y+19=0

Step-by-step explanation:

(y-4)=(-3-4/2-(-1))*(x+1)

y-4=-7/3*(x+1)

3y-12 = 7x+7

7x+7-3y+12=0

7x-3y+19=0

Answer 2

Answer:

required equation is 7x+3y-5

Step-by-step explanation:

first we have to find the gradient m = (y2 - y1)/(x2 - x1) ; where (x1 , y1) , (x2 , y2) are given two points

Here given points are (2,-3) and (-1,4)

hence gradient of given points is  m = (4-(-3)) / (-1-2) = 4+3 / -1-2 = -(7/3)

equation of  line ,

y-y1 = m( x-x1)

⇒ y-(-3) = (-7/3) (x-2)

⇒ 3(y+3) = -7(x-2)

⇒ 3y+9+7x-14 = 0

⇒ 7x+3y-5 = 0