find the equation of the line through (4,-5) and parallel to the line joining the points (3,7) and (-2,4).
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Answered by
2
Answer:
Slope of the given line = slope of AB=
−2−3
4−7
=
5
3
. Thus, m=
5
3
∴ required equation is
x−4
y+5
=
5
3
⇔3x−5y−37=0
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0
) and parallel to the line joining the points (3,7) and (-2,4).
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