Find the equation of the line through the intersection of lines 2x —y = 1 and 2y -9 and making an angle 300 with positive direction of x- axis.
Answers
EXPLANATION.
Equation of the line through the intersecting of lines,
(1) = 2x - y = 1.
(2) = 2y - 9 = 0.
Makes an angle 30° with positive x-axis.
From equation (2) we get,
⇒ 2y - 9 = 0.
⇒ 2y = 9.
⇒ y = 9/2.
Put the value of y = 9/2 in equation (1) we get.
⇒ 2x - 9/2 = 1.
⇒ 2x = 1 + 9/2.
⇒ 2x = 2 + 9/2.
⇒ 2x = 11/2.
⇒ x = 11/4.
As we know that,
Slope = m = tan∅.
⇒ m = tan(30°).
⇒ m = 1/√3.
As we know that,
Equation of line = (y - y₁) = m(x - x₁).
Put the value in the equation, we get.
⇒ (y - 9/2) = 1/√3 (x - 11/4).
⇒ √3(2y - 9/2) = (4x - 11/4).
⇒ √3(2y - 9) = (4x - 11/2).
⇒ 2√3(2y - 9) = 4x - 11.
⇒ 4√3y - 18√3 = 4x - 11.
⇒ 4x - 4√3y + 7 = 0.
...❀A NS WE R❀...
Equation of the line through the interesecting of the line:
☆(1) 2x —y = 1
☆(2) 2y -9 = 0
make an angle 30° with positive x axis.
from equation (2) we get,
➣2 y - 9 = 0
➣2 y = 9
➣y = 9/2
put the value of y = 9/2 in equation 1 we have get :
➢2 x - 9/2 = 1
➢2 x = 1 + 9/2
➢2 x = 2 + 9/2
➢2 x = 11/2
➢x = 11/4
➱( y - 9/2 )= 1 √(x -11 / 4)
➱√3 ( 2 y - 9/2) = 4 x - 11/4
➱√3 ( 2 y - 9 )= 4 x - 11/4
➱2√3 ( 2 y - 9 ) = 4 x - 11
➱4√3 y - 18 √3 = 4 x - 11