Question

Find the equation of the line through the point (3,2 ) and parallel to the line 2x -3y -2 =0

Answer 1

Answer:

2x - 3y = 0

Step-by-step explanation:

slope of line 2x -3y -2 =0 is given by

$m = - \frac{2}{ - 3} = \frac{2}{3}$

given point (3,2), let

${x}^{.} = 3 \: \: \: and \: \: {y}^{.} = 2$

using one point slope formula, the equation of required line is given by :

$y - {y}^{.} = m(x - {x}^{.} )$

$y - 2 = \frac{2}{3} (x - 3)$

$3y - 6 = 2x - 6$

$- 6 + 6 = 2x - 3y$

$2x - 3y = 0$