Question

find the equation of the line through the point of intersection of the lines 3x-5=5 and x-2y+5=0, perpendicular to the line 2x2x+3y+4=0​

Answer 1

Answer:

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Step-by-step explanation:

This lines 5x−6y−1=0 and 3x+2y+5=0 intersect at the point (−1,−1).

The slope of the line 3x−5y+11=0 is 3/5.

So, the slope of a line perpendicular to it is −5/3.

Hence, the equation of the required line is

(y−y

1

)=m(x−x

1

)

y+1=−5/3(x+1)

⟹ 5x+3y+8=0