Question

Find
the equation of the line which
has y intercept -3 and is parallell
to the line
x+y+1=0

Answer 1

Given :-

☆ A line L which has y intercept - 3 and which is parallel to the line 'l' x + y + 1 = 0

To find :-

☆The equation of line L

Solution:-

$\tt \ \: :  ⟼ Slope \: of \: line \: l \: = - \dfrac{1}{1} = - 1$

$\tt \ \: :  ⟼ Now, \: l \: \parallel \: L$

$\tt\implies \:Slope \: of \: L \: = \: Slope \: of \: l$

$\tt\implies \:Slope \: of \: L \: (m) = - 1$

$\tt \ \: :  ⟼ Now, \: equation \: of \: line \: having \: y \: - \: intercept \\ \tt \ \: (c) \: = - 3 \: and \: having \: Slope(m) \: - 1 \: is \: given \: by \: \: \:$

$\tt\implies \:y \: = \: mx \: + \: c$

$\tt\implies \:y \: = \: - 1 \times x + ( - 3)$

$\tt\implies \:y = - x - 3$

$\tt\implies \:x + y + 3 = 0$