Find the equation of the line which is at a perpendicular distance of 5 units from the origin and the angle made by the perpendicular with the positive x-axis is 30°
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If pisthe length of the normal from the origin to a line and ωis the angle made by the normal with the positive direction of thex-axis,then the equation of the line is given by xcosω +ysinω= p.
Here, p= 5 units and ω= 30°
Thus, therequired equation of the given line is
xcos 30° + y sin 30° = 5
x root3/2+y/2=5
root3 x +y =10
Here, p= 5 units and ω= 30°
Thus, therequired equation of the given line is
xcos 30° + y sin 30° = 5
x root3/2+y/2=5
root3 x +y =10
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