Question

find the equation of the line which is parallel to 3x -2y +5 =0 and passes through the point (5,-6)

class 11 maths

Answer 1

Solution :

Equation of the line parallel to

3x-2y+5=0 is

3x - 2y + k = 0

Substitute ( 5,-6 ) in the equation we

get ,

3(5) - 2(-6) + k = 0

=> 15 + 12 + k = 0

=> 25 + k = 0

=> k = -25

Therefore ,

Required equation is 3x - 2y - 25 = 0

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