Question

Find the equation of the line which is parallel to the line x+4y-1=0 and passes through the point (1, 2).

Answer 1

Answer:

x+4y = 9

Step-by-step explanation:

RULE: - Parallel lines have the same slope

Arranging the equation ( x+4y-1=0) in the form: y = mx + c, where m is the slope of the line

x+4y = 1

∴4y = -x+1

∴y = (-1/4)x + (1/4)

∴ m = (-1/4)

For the line passing (1, 2), equation can be derived using this formula:

 (y-y1) = m(x-x1)

∴ y-2  = (-1/4)(x-1)

∴ 4*(y-2) = -1*(x-1)

∴ 4y-8 = -x+1

∴x+4y = 8+1

∴x+4y = 9 is the final answer