Question

Find the equation of the line which is perpendicular to the line by -ax = ab at the
point where this line meets y-axis.

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Answer 1

Answer:

Perpendicular line is bx+ay=a^2 and the line meets y-axis at (0,a)

Step-by-step explanation:

Given equation by-ax=ab

This equation can be written as y=(a/b)x+a

it is in the form y= mx+c

For perpendicular lines

m1 x m2= -1

a/b x m2 =-1

therefore m2= -b/a

the equation of perpendicular line is

y=m2x+c

y=(-b/a)x+a

therefore bx+ay=a^2

and on y-axis abssica is 0

therefore ay=a^2

y=a

hence point is (0,a)