Question

find the equation of the line which is perpendicular to the line x/4-y/6= 1 at the point where this line meets y axis... solve this ❤️​

Answer 1

Given:-

• The equation of a line perpendicular to the line x/4 + y/6 = 1.

To find:-

• Find the equation of the line ...?

Solutions:-

• The equation of the given line is x/4 + y/6 = 1.

This equation can also be 3x + 2y - 12 = 0

y = -3/2 x + 6, the form y = mx + c

Therefore,

Slope of the given line = -3/2

Slope of line perpendicular to the given line

=> -1/(-3/2)

=> 2/3

• Let the given line intersect the y - axis at (0, y) on substitution x with o in the equation of the given line, we obtain.

The given line intersect the y - axis at (0, 6)

The equation of the line that has a slope at 2/3 and passes through points (o, 6).

=> (y - 6) = 2/3 (x - 0)

=> 3(y - 6) = 2x

=> 3y - 18 = 2x

=> 2x - 3y + 18 = 0

Hence, the required equation of the line is 2x - 3y + 18 = 0.

Answer 2

Answer:

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