Question

find the equation of the line which makes intercepts -3 &2 on the co-ordinate axes respectively​

Answer 1

Question :-

• Find the equation of the line which makes intercepts -3 &2 on the coordinate axes respectively

Answer :-

$\large \implies \bf2x - 3y + 6 = 0$

Solution :-

Intercept form :-

$</u><u>\</u><u>large</u><u> \implies \bf \dfrac{x}{a} + \dfrac{y}{b} = 1$

Where ,

• x is a intercept of a

• y is a intercept of b

Now :-

$\large\implies \bf \dfrac{x}{ - 3} + \dfrac{y}{2} = 1$

$\\ \\ \large\implies \bf \frac{ - 2x + 3y}{6} = 1$

$\\ \\ \large\implies \bf - 2x + 3y = 6$

$\\ \\ \large \implies \bf 2x - 3y + 6 = 0$

$\therefore$ So, this is the required eqation.