Question

find
the equation
of
the line which passes
< through the point (5, 6) and makes intercept
axes which
which are
equal in magnitude
but opposite in sign.
the​

Answer 1

Answer:

y-x=1

Step by Step explanation:-

Here there may be two cases

Here there may be two casescase-1:

x/-a+y/a=1

So,

y-x=a

The above lines passes through a point (5,6) such that,

The above lines passes through a point (5,6) such that,6−5=a

The above lines passes through a point (5,6) such that,6−5=a⇒a=1

The above lines passes through a point (5,6) such that,6−5=a⇒a=1Therefore, required equation is y−x=1

The above lines passes through a point (5,6) such that,6−5=a⇒a=1Therefore, required equation is y−x=1case-2:

x/a+y/-a

⇒x−y=a

⇒x−y=aThe above lines passes through a point (5,6) such that,

⇒x−y=aThe above lines passes through a point (5,6) such that,5−6=a

⇒x−y=aThe above lines passes through a point (5,6) such that,5−6=a⇒a=−1

⇒x−y=aThe above lines passes through a point (5,6) such that,5−6=a⇒a=−1Therefore, required equation is x−y=−1