Find the equation of the line which passes through ( 2, 2.3^(1/2) ) and is inclined with the x-axis at an angle of 75°.
Answers
Given : Line passes through ( 2, 2√3 ) and is inclined with the x-axis at an angle of 75°.
To find : Equation of line
Solution:
Equation of a line passing through point (x₁ , y₁)
y - y₁ = m(x - x₁)
m = Slope of line = tan 75°
x₁ = 2 , y₁ = 2√3
m = tan 75°
= tan(45° + 30°)
= (Tan 45° + tan 30°)/(1 - Tan45°Tan30°)
= ( 1 + 1/√3) /( 1 - 1/√3)
= (√3 + 1)/(√3 - 1)
= (3 + 1 + 2√3)/2
= 2 + √3
y - y₁ = m(x - x₁)
=> y - 2√3 = (2 + √3)(x - 2)
=> y - 2√3 = (2 + √3)x - 4 - 2√3
=> y = (2 + √3)x - 4
y = (2 + √3)x - 4 the equation of the line which passes through ( 2, 2√3) and is inclined with the x-axis at an angle of 75°.
Learn More:
Show that the equation of the line having slope m and making x ...
https://brainly.in/question/13903485
What is the slope of the line joining the points(2,0) and(-2,0) - Brainly ...
https://brainly.in/question/13724435