Question

Find the equation of the line which passes through (7,3) and (2.1)​

Answer 1

Answer:-

Given:-

A line passes through (7 , 3) and (2 , 1).

We know that,

Equation of a line :- y - y₁ = m(x - x₁)

Where,

• (x₁ , y₁) is first point which the line passes.
• m is the slope of the line.

We know,

Slope of a line passing through (x₁ , y₁) & (x₂ , y₂) is:-

m = (y₂ - y₁) /(x₂ - x₁)

Let,

• x₁ = 7
• y₁ = 3
• x₂ = 2
• y₂ = 1

Hence,

⟹ m = (1 - 3)/(2 - 7)

⟹ m = - 2/ - 5

⟹ m = 2/5

Therefore,

Required equation of the line:-

⟹ y - 3 = (2/5) (x - 7)

⟹ 5(y - 3) = 2(x - 7)

⟹ 5y - 15 = 2x - 14

⟹ 5y - 2x - 15 + 14 = 0

⟹ 5y - 2x - 1 = 0

∴ The equation of the line passing through the given points is 5y - 2x - 1 = 0.