Question

Find the equation of the line which passes through P(1,-7) amd meets the axes at A & B so that 4AP-3BP=0

Answer 1

Answer:

28x−3y=49

Step-by-step explanation:

Let the equation of the line be

x y

— = — = 1-----[1]

a b

4AP−3BP=0⇒AP/BP=3/4

Therefore P divides AB internally in the ratio 3:4

Thus coordinates of P are given by

P= [ 4a+3(0)/ 4+3] , [4(0)+3b/7]

(1,−7)= (4a/7 ,3b/7)

∴ 1 = 4a/7,−7 =3b/7

⇒a=7/4 ,b= −49/3

Substituting in [1]

we have, ⇒28x−3y=49