Question

Find the equation of the line which passes through the points (6, 4) and (2, 12).​

Answer 1

Answer:

2x-y-16= 0 is your answer

Step-by-step explanation:

Step 1: Find the slope of the line.

formula:

m= y2–y1 / x2–x1

= 12–4/2–6

= 8/-4

= –2

So slope, 'm' = -2

Step 2: Use the slope to find the y-intercept.

we use:

y = mx+b ......(1)

Substitute x= 6 and y= 4 in eq (1)

4= (-2)(6)+ b

4= -12+b

b=4+12

b=16

Now, substituting the value of b in eq(1)

We get:

Y= -2x + 16

2x-y-16= 0 is the equation required

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