Question

find the equation of the line which passes through the line(-2,3) and is perpendicular to the line 2 X + 3 Y + 6 equal to zero​

Answer 1

Answer:

Step-by-step explanation:

Slope of required equation =  

Slopeofthe2x+3y+4=0

−1

​

 

⇒m=  

3

−2

​

 

−1

​

=  

2

3

​

 

Equation of line with slope  

2

3

​

 and passing through point (−2,3)

y−3=  

2

3

​

(x+2)

⇒2y−6=3x+6

⇒3x−2y+12=0

​

 

Hence, this is the answer.