Question

Find the equation of the line which passes through the point (-2,3) and is
perpendicular to the line 2x+3y+4=0​

Answer 1

Answer:

y = (3/2)x + 6

Step-by-step explanation:

Line perpendicular to given line has slope which is opposite reciprocal to slope of given line.

y = mx + b , "m" is slope and "b" is y-intercept.

y - $y_{1}$ = m(x - $x_{1}$)

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Solve for "y" given equation:

y = - $\frac{2}{3}$ x - $\frac{4}{3}$ , m = - 2/3 , then slope of perpendicular line is (3/2)

y - 3 = (3/2)(x + 2) ===> y = (3/2)x + 6 is equation of perpendicular line passing through (- 2, 3)