Question

Find the equation of the line which passing through the point (-4, 3) with slope 1÷2
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Answer 1

let the number be x

Answer:

the point

-4+3

slop1÷2

therefore -4+3=1÷2

1-(-4)=2×3

5x=6

x=6/5 ans

Answer 2

Answer:

Slope of line = 1/2

Point (x',y') = (-4,3)

Equation of the line = ?

Formula :- (x-x')m = y-y'

Hence, equation of line = 1/2(x-(-4)) = y-3

⇒ x+4 = 2y-6

⇒ x-2y = -6-4

⇒ x-2y = -10

⇒ x-2y+10 = 0

Formulas:

• Horizontal lines : y=a, y=(-a)
• Vertical lines : x=a, x=(-a)
• Point slope : (x-x')m = (y-y')
• Two point slope : y-y1 = (y2-y1)/(x2-x1) × (x-x1)
• Slope intercept form : If Y intercept is c or -c, then y=mx+c or y=mx-c AND If X intercept is d or -d, then y=m(x-d) or y=m(x+d)
• Intercept form : x/a+y/b=1
• Normal form : xcos∅+ysin∅=p