Question

find the equation of the line whose y_intercept is -3and wich is perpendicular to the line joining the points (-2,3)and(-3,6)​

Answer 1

Answer:

x-3y-9=0

Step-by-step explanation:

let the two given points (-2,3) & (-3,6) br P and Q .The line may be XY.

for A & B,

y=mx+c

3=-2m+c

6=-3m+c

by solving , we get-

m(AB)=-3 and y-intercept -3

m(xy)= - (1/m(XY))

m(xy)=1/3

now by formula for line XY, y=mx+c

y=x/3-3

x-3y-3=0 (ans)