Find the equation of the line whose y-intercept is 4 and parallel to the line 2x-3y-7=0
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Answered by
11
so when lines are parallel their slopes are equal
m = m₁
so the slope of line 2x - 3y - 7 = 0 ,m₁ = -2/3
so using y = mx + c
y = (-2/3)x + 4
3y = -2x + 12
2x + 3y - 12 = 0 ANSWER
m = m₁
so the slope of line 2x - 3y - 7 = 0 ,m₁ = -2/3
so using y = mx + c
y = (-2/3)x + 4
3y = -2x + 12
2x + 3y - 12 = 0 ANSWER
Anonymous:
what is the slope of the line ax+by+c=0?
-b/a
wait.
but the slopes are 3/2 and 2/3 then..
how can they be parallel?
ok so slope is -a/b?
slope is -b/a for ax+by+c=0
sorry i wrote the wrong slope in comment
sorry...slope is -a/b. you are correct.
god!! nice discussion souvik.
Answered by
3
a line parallel to 2x-3y-7=0 is 2x-3y+c=0.
this passes through (0,4)
2*0-3*4+c=0
=>c=12
line is 2x-3y+12=0.
this passes through (0,4)
2*0-3*4+c=0
=>c=12
line is 2x-3y+12=0.
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