Question

Find the equation of the line with the slope m=5/3 that contains the points (-6,-12)

Answer 1

Answer:

Let (x,y) and (-6,-12) be two points of the line.

We know,

=> (x2 - x1)/(y2 - y1) = 5/3

=> (-6 - x)/(-12 - y) = 5/3

By Cross Multiplying,

We get,

=> 3 (- 6 - x) = 5 (- 12 - y)

=> -18 - 3x = -60 -th

=> 3x - 5y - 42 = 0 (or) 3x - 5y = 42 is the equation for the line.