Question

Find the equation of the line with x intercept 3 units and a point (3,-2) on it?​

Answer 1

so the answer is =x/-3 + y/1 = 1 => x - 3y +3 = 0.

Step-by-step explanation:

We know that equation of a straight line in intercept form is (x/a)+(y/b)=1; where a is X intercept and b is Y intercept, made by the straight line.

Given, X intercept is (-3) units and the straight line passes through the point (3,2).

(x/a)+(y/b)=1

=> {3/(-3)}+(2/b)=1 => 2/b =2 => b= 1

Hence, the equation of the straight line will be the ={x/(-3)}+(y/1) = 1 => -x+3y=3 => x-3y+3=0