Find the equation of the lines OA, OB, OC and BD from the given figure, in which OABC is a square of side 5 units and OC=CD.
Answers
Given : A graph showing OABC square of side 5 units
To find : equation of the lines OA, OB, OC and BD
Solution:
O is origion (0 , 0)
C = ( 5 , 0)
A = (0 , 5)
B = ( 5 , 5)
Equation of OC is y = 0 as it on x axis
Equation of OA is x = 0 as its on y - axis
Slope of OB = (5 - 0)/(5 - 0) = 1
OB Equation = y - 0 = 1 (x - 0)
=> y = x
=> x - y = 0
OC = OD
=> D = ( 10 , 0)
B = ( 5 , 5)
Slope of BD = ( 5 - 0)/(5 - 10) = - 1
y - 0 = - 1 ( x - 10)
=> y = -x + 10
=> x + y = 10
OC is y = 0
OA is x = 0
OB is x = y
BD is x + y = 10
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Answer:
OA : x = 0, OB : y = x, OC : y = 0, BD : x+y = 10
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