Math, asked by nt8151, 1 year ago

Find the equation of the lines which pass through the point (-2,5) and are equally inclined to the coordinate axes.

Answers

Answered by TPS
24
There are two lines possible passing through any point on coordinate plane which are equally inclined to the coordinate axes. 
The slopes of the lines are 1 and -1.

let the equation of the required line be y=mx+c

for slope(m) = 1,
so the equation becomes y=x+c

as it passes through (-2,5)
⇒ 5 = -2 + c
⇒ c = 5+2 = 7
So one of the equation is 
y = x+7

for slope(m) = -1,
so the equation becomes y=-x+c

as it passes through (-2,5)
⇒ 5 = -(-2) + c
⇒ 5 = 2 + c
⇒ c = 5-2 = 3
So other equation is 
y = -x+3

TPS: if you have any doubt, let me know
nt8151: yes why m is -1 and 1?
TPS: when a line is equally inclined to both axes, the angle it will make with x-axis is 45 degree and -45 degrees. so the slopes(tan 45 and tan(-45)) are 1 and -1
TPS: you can understand better if you try to visualize the lines on coordinate plane.....or draw them...
nt8151: k.i will
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