Question

Find the equation of the lines which passes through the point (3, 4) and cuts off
intercepts from the coordinate axes such that their sum is 14

Answer 1

Answer:

Here You Go Dude!

Step-by-step explanation:

Answer 2

equation of the line

X/a+Y/b=1. (1)

given a+b=14

b= 14-a putting this in (1)

X/a+Y/(14-a)=1

It passes through (3 4)

3/a+4/(14-a)=1

42-3a+4a=a(14-a)

a+42=14a-a²

a²-13a+42=0

a²-7a-6a+42=0

a(a-7)-6(a-7)=0

(a-7) (a-6)=0

Therefore

a=7 or a= 6

Put the value a=7 in (1)

X/7+Y/7=1

X+Y=7

Again put a=6 in(1)

X/6+Y/8=1

X