Find the equation of the locus of P , if A = (4,0),B=(-4,0) and PA-PB =4
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Answered by
27
A=4,0
B=-4,0
mod PA-PB=4
PA-PB=+_4
PA=+_4+PB
PA^2=16+PB^2+_8PB
PA^2-16+PB^2=+_8PB
(x-4)^2+y^2-(x+4)^2-y^2-16=+_8
x^2+16-8x-(x^2+16+8x)-16=+_8
16-16-8x-8x-16=+_8
-16x-16=+_8
16(-x-1)=+_8
-x-1=+_1/2
squaring on both sides
-(x-1))^2=+1/2PB^2
-(x^2-2x+1)=1/2(x+4)^2+y^2
-x^2+2x-1=1/4(x^2+8x+16+y^2)
-3x^2/2-y^2/2=3 is the locus of P
@skb
B=-4,0
mod PA-PB=4
PA-PB=+_4
PA=+_4+PB
PA^2=16+PB^2+_8PB
PA^2-16+PB^2=+_8PB
(x-4)^2+y^2-(x+4)^2-y^2-16=+_8
x^2+16-8x-(x^2+16+8x)-16=+_8
16-16-8x-8x-16=+_8
-16x-16=+_8
16(-x-1)=+_8
-x-1=+_1/2
squaring on both sides
-(x-1))^2=+1/2PB^2
-(x^2-2x+1)=1/2(x+4)^2+y^2
-x^2+2x-1=1/4(x^2+8x+16+y^2)
-3x^2/2-y^2/2=3 is the locus of P
@skb
Answered by
8
Answer:
please ignore the minor mistakes made
hope it helps!!!!!!
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