Question

Find the equation of the median AD of the AABC whose vertices are A(2,5),B(-4,9) and C(-2,-1)

Answer 1

Step-by-step explanation:

$x - 5y + 23= 0$

coordinates of point D are

$( \frac{ - 4 - 2}{2} \: \: \: \: \frac{9 - 1}{2} ) \\ \\ ( - 3 \: \: \: \: 4)$

therefore equation of Median AD IS

$(y - 4) = \frac{5 - 4}{2 + 3} (x + 3) \\ \\ (y - 4) = \frac{1}{5} (x + 3) \\ \\ 5(y - 4) =( x + 3) \\ \\ 5y - 20= x + 3 \\ \\ x + 3 - 5y + 20= 0 \\ x - 5y + 23 = 0$