Question

Find the equation of the normal to the curve y 2 4x which passes through the point 1 2

Answer 1

Step-by-step explanation:

solution:

y^2=4x

differentiating wt x we have

dy/dx=4/2y=2/y

the slope of normal at point (1,2 ) is

-1/(dy/dx) at the point (1,2)=-1/1=-1

therefore equation of normal at the point (1,2) is y-2=-1(x-1)

x+y-3=0 is the required euation