Question

find the equation of the parabola if the focus is at (-6,-6)and vertex is at(-2,-2)​

Answer 1

Answer:

Dec 29, 2016 - All the lines must be in their normalised form,i.e., (ax+by+z)/sqrt(a^2+b^2). For given parabola, equation of axis: Slope=(6–2)/(-6-(-2))=-1, x+y=0. Equation of line perpendicular to axis and passing through vertex: slope=1, x-y+4=0.