Find the equation of the parabola that satisfies the Given condition;.
1. Vertex (0,0); focus (3,0)
2.Focus (6,0); directrix x= -6
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Hey there,
Given Vertex (0,0)(0,0) and Focus (3,0)(3,0) Since the vertex is the origin and the focus lies on the positive x-axis, →→ x-axis is the axis of the parabola. The parabola is of the form y2=4axy2=4ax.
Since Focus = (3,0)→a=3(3,0)→a=3 Therefore the equation of the parabola is y2=4×3x=12x
Hope this helps!
Given Vertex (0,0)(0,0) and Focus (3,0)(3,0) Since the vertex is the origin and the focus lies on the positive x-axis, →→ x-axis is the axis of the parabola. The parabola is of the form y2=4axy2=4ax.
Since Focus = (3,0)→a=3(3,0)→a=3 Therefore the equation of the parabola is y2=4×3x=12x
Hope this helps!
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