find the equation of the parabola whose focus is (2,3) and directrix is x-2y-6=0
Answers
Answered by
2
(x+1)2+(y+2)2=[x−2y+312+22−−−−−√]2(x+1)2+(y+2)2=[x−2y+312+22]2
5[(x2+2x+1)+(y2+2y+4)]=(x−2y+3)25[(x2+2x+1)+(y2+2y+4)]=(x−2y+3)2
⇒5[(x2+2x+1)+(y2+4y+4)]=x2+4y2+9−4xy−12y+6x⇒5[(x2+2x+1)+(y2+4y+4)]=x2+4y2+9−4xy−12y+6x
⇒5x2+10x+5+5y2+20y+20=x2+4y2+9−4xy−12y+6x⇒5x2+10x+5+5y2+20y+20=x2+4y2+9−4xy−12y+6x
4x2+y2+4xy+4x+32y+16=04x2+y2+4xy+4x+32y+16=0
Similar questions