Question

find the equation of the parabola whose vertex is at the point (3,-2)and focus at the point (6,2)​

Answer 1

Answer:

Clearly we can see that axis of parabola is parallel to y-axis

Assume the equation of parabola to be :(x−h)

2

=4b(y−k)

Focus =(h,k+b)=(3,1)

Vertex =(h,k)=(3,−2)

⇒h=3,k=−2,b=3

⇒equation of parabola is : (x−3)

2

=12(y+2)